Optimal. Leaf size=201 \[ -\frac{\left (10 a^2+11 b^2\right ) \sin (c+d x) \cos ^7(c+d x)}{80 d}+\frac{\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos ^5(c+d x)}{480 d}+\frac{\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{384 d}+\frac{\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos (c+d x)}{256 d}+\frac{1}{256} x \left (10 a^2+3 b^2\right )+\frac{2 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{b^2 \sin (c+d x) \cos ^9(c+d x)}{10 d} \]
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Rubi [A] time = 0.26689, antiderivative size = 201, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.276, Rules used = {2911, 2565, 14, 3200, 455, 385, 199, 203} \[ -\frac{\left (10 a^2+11 b^2\right ) \sin (c+d x) \cos ^7(c+d x)}{80 d}+\frac{\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos ^5(c+d x)}{480 d}+\frac{\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{384 d}+\frac{\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos (c+d x)}{256 d}+\frac{1}{256} x \left (10 a^2+3 b^2\right )+\frac{2 a b \cos ^9(c+d x)}{9 d}-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{b^2 \sin (c+d x) \cos ^9(c+d x)}{10 d} \]
Antiderivative was successfully verified.
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Rule 2911
Rule 2565
Rule 14
Rule 3200
Rule 455
Rule 385
Rule 199
Rule 203
Rubi steps
\begin{align*} \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx &=(2 a b) \int \cos ^6(c+d x) \sin ^3(c+d x) \, dx+\int \cos ^6(c+d x) \sin ^2(c+d x) \left (a^2+b^2 \sin ^2(c+d x)\right ) \, dx\\ &=\frac{\operatorname{Subst}\left (\int \frac{x^2 \left (a^2+\left (a^2+b^2\right ) x^2\right )}{\left (1+x^2\right )^6} \, dx,x,\tan (c+d x)\right )}{d}-\frac{(2 a b) \operatorname{Subst}\left (\int x^6 \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=\frac{b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}-\frac{\operatorname{Subst}\left (\int \frac{b^2-10 \left (a^2+b^2\right ) x^2}{\left (1+x^2\right )^5} \, dx,x,\tan (c+d x)\right )}{10 d}-\frac{(2 a b) \operatorname{Subst}\left (\int \left (x^6-x^8\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{2 a b \cos ^9(c+d x)}{9 d}-\frac{\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac{b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac{\left (10 a^2+3 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^4} \, dx,x,\tan (c+d x)\right )}{80 d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{2 a b \cos ^9(c+d x)}{9 d}+\frac{\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac{\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac{b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac{\left (10 a^2+3 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^3} \, dx,x,\tan (c+d x)\right )}{96 d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{2 a b \cos ^9(c+d x)}{9 d}+\frac{\left (10 a^2+3 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{384 d}+\frac{\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac{\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac{b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac{\left (10 a^2+3 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right )^2} \, dx,x,\tan (c+d x)\right )}{128 d}\\ &=-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{2 a b \cos ^9(c+d x)}{9 d}+\frac{\left (10 a^2+3 b^2\right ) \cos (c+d x) \sin (c+d x)}{256 d}+\frac{\left (10 a^2+3 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{384 d}+\frac{\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac{\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac{b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac{\left (10 a^2+3 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\tan (c+d x)\right )}{256 d}\\ &=\frac{1}{256} \left (10 a^2+3 b^2\right ) x-\frac{2 a b \cos ^7(c+d x)}{7 d}+\frac{2 a b \cos ^9(c+d x)}{9 d}+\frac{\left (10 a^2+3 b^2\right ) \cos (c+d x) \sin (c+d x)}{256 d}+\frac{\left (10 a^2+3 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{384 d}+\frac{\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac{\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac{b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}\\ \end{align*}
Mathematica [A] time = 0.880684, size = 193, normalized size = 0.96 \[ \frac{5040 a^2 \sin (2 (c+d x))-2520 a^2 \sin (4 (c+d x))-1680 a^2 \sin (6 (c+d x))-315 a^2 \sin (8 (c+d x))+12600 a^2 d x-15120 a b \cos (c+d x)-6720 a b \cos (3 (c+d x))+1080 a b \cos (7 (c+d x))+280 a b \cos (9 (c+d x))+630 b^2 \sin (2 (c+d x))-1260 b^2 \sin (4 (c+d x))-315 b^2 \sin (6 (c+d x))+\frac{315}{2} b^2 \sin (8 (c+d x))+63 b^2 \sin (10 (c+d x))+6300 b^2 c+3780 b^2 d x}{322560 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.044, size = 183, normalized size = 0.9 \begin{align*}{\frac{1}{d} \left ({a}^{2} \left ( -{\frac{\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{8}}+{\frac{\sin \left ( dx+c \right ) }{48} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{5\,dx}{128}}+{\frac{5\,c}{128}} \right ) +2\,ab \left ( -1/9\, \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{7}-{\frac{2\, \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{63}} \right ) +{b}^{2} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{10}}-{\frac{3\,\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{80}}+{\frac{\sin \left ( dx+c \right ) }{160} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{3\,dx}{256}}+{\frac{3\,c}{256}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.00384, size = 171, normalized size = 0.85 \begin{align*} \frac{210 \,{\left (64 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 120 \, d x + 120 \, c - 3 \, \sin \left (8 \, d x + 8 \, c\right ) - 24 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} + 20480 \,{\left (7 \, \cos \left (d x + c\right )^{9} - 9 \, \cos \left (d x + c\right )^{7}\right )} a b + 63 \,{\left (32 \, \sin \left (2 \, d x + 2 \, c\right )^{5} + 120 \, d x + 120 \, c + 5 \, \sin \left (8 \, d x + 8 \, c\right ) - 40 \, \sin \left (4 \, d x + 4 \, c\right )\right )} b^{2}}{645120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.86274, size = 379, normalized size = 1.89 \begin{align*} \frac{17920 \, a b \cos \left (d x + c\right )^{9} - 23040 \, a b \cos \left (d x + c\right )^{7} + 315 \,{\left (10 \, a^{2} + 3 \, b^{2}\right )} d x + 21 \,{\left (384 \, b^{2} \cos \left (d x + c\right )^{9} - 48 \,{\left (10 \, a^{2} + 11 \, b^{2}\right )} \cos \left (d x + c\right )^{7} + 8 \,{\left (10 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{5} + 10 \,{\left (10 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{3} + 15 \,{\left (10 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{80640 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 39.1656, size = 529, normalized size = 2.63 \begin{align*} \begin{cases} \frac{5 a^{2} x \sin ^{8}{\left (c + d x \right )}}{128} + \frac{5 a^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{32} + \frac{15 a^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{64} + \frac{5 a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{32} + \frac{5 a^{2} x \cos ^{8}{\left (c + d x \right )}}{128} + \frac{5 a^{2} \sin ^{7}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{128 d} + \frac{55 a^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{384 d} + \frac{73 a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{384 d} - \frac{5 a^{2} \sin{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} - \frac{2 a b \sin ^{2}{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{7 d} - \frac{4 a b \cos ^{9}{\left (c + d x \right )}}{63 d} + \frac{3 b^{2} x \sin ^{10}{\left (c + d x \right )}}{256} + \frac{15 b^{2} x \sin ^{8}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{256} + \frac{15 b^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{128} + \frac{15 b^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{128} + \frac{15 b^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{8}{\left (c + d x \right )}}{256} + \frac{3 b^{2} x \cos ^{10}{\left (c + d x \right )}}{256} + \frac{3 b^{2} \sin ^{9}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{256 d} + \frac{7 b^{2} \sin ^{7}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{128 d} + \frac{b^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{10 d} - \frac{7 b^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} - \frac{3 b^{2} \sin{\left (c + d x \right )} \cos ^{9}{\left (c + d x \right )}}{256 d} & \text{for}\: d \neq 0 \\x \left (a + b \sin{\left (c \right )}\right )^{2} \sin ^{2}{\left (c \right )} \cos ^{6}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19813, size = 255, normalized size = 1.27 \begin{align*} \frac{1}{256} \,{\left (10 \, a^{2} + 3 \, b^{2}\right )} x + \frac{a b \cos \left (9 \, d x + 9 \, c\right )}{1152 \, d} + \frac{3 \, a b \cos \left (7 \, d x + 7 \, c\right )}{896 \, d} - \frac{a b \cos \left (3 \, d x + 3 \, c\right )}{48 \, d} - \frac{3 \, a b \cos \left (d x + c\right )}{64 \, d} + \frac{b^{2} \sin \left (10 \, d x + 10 \, c\right )}{5120 \, d} - \frac{{\left (2 \, a^{2} - b^{2}\right )} \sin \left (8 \, d x + 8 \, c\right )}{2048 \, d} - \frac{{\left (16 \, a^{2} + 3 \, b^{2}\right )} \sin \left (6 \, d x + 6 \, c\right )}{3072 \, d} - \frac{{\left (2 \, a^{2} + b^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{256 \, d} + \frac{{\left (8 \, a^{2} + b^{2}\right )} \sin \left (2 \, d x + 2 \, c\right )}{512 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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